Square Pattern
#include<iostream>
using namespace std;
int main(){
int n;
cin>>n;
int N=(2*n)-1;
int s = 0;
int e = N-1;
int a[N][N];
while(n>0){
for(int i=s;i<=e;i++){
for(int j=s;j<=e;j++){
if(i==s || i==e || j==s || j==e){
a[i][j]=n;
}
}
}
s++;
e--;
n--;
}
for(int i=0;i<N;i++){
for(int j=0;j<N;j++){
cout<<a[i][j]<<" ";
}
cout<<endl;
}
return 0;
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